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2011-02-10 14:19:36 GMT 2011-02-14 13:31:17 (GMT -05:00) Eastern Time (US & Canada) Yes (click here to learn more about ) Closed - Note: This project was manually closed by the voice seeker before it reached its original deadline. 0 0 9 direct invitation(s) have been sent by the voice seeker resulting in 0 audition(s) and/or proposal(s) so far. Voice123 SmartCast is seeking 10 auditions and/or proposals for this project (approx.) Invitations sent by SmartCast have resulted in 0 audition(s) and/or proposal(s) so far.
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Let’s pretend that we have a light, say a laser light at the bottom of a pool. This would probably never happen but it makes T I R easier to explain.
Anyway, using our laser goggles, let’s watch the laser light through the water and see what happens as the incident angle of the laser light is increased.
See how the refracted rays are becoming dimmer and the reflected rays are getting brighter as the incident angle is increased.
Let’s stop turning the laser when the reflected angle is 90 degrees to the incident laser light.
Okay (draw this word out, like you are waiting for something to stop)… there!
Hmmm? There’s a lot of laser light coming through the water meaning there is a lot less refraction going on.
Let’s start increasing the incidence angle again, and as the incidence angle increases, the refraction angle will continue to approach 90 degrees until (draw the word until out), there!
Now we can’t see the laser light coming through the water anymore.
So what is the incident angle of laser light that will finally cause the light to disappear and does this angle have a name?
Well…this angle does have a name and it’s called the critical angle.
We can find out what the critical angle is by using Snell’s Law. I just love Snell’s law. It is so useful for figuring out so many different things about light.
Since the maximum possible angle of refraction is 90 degrees, theta sub ‘r’ will always equal 90 degrees when solving for the critical angle.
Ok, so ‘n’ sub ‘i’ is one point three three, the refractive index for water and ‘n’ sub ‘r’ is one, the refractive index for air.
Getting everything on one side and using inverse sine to solve for theta ‘i’ the incidence angle…we would get, umm just a sec while I use my calculator (pause) ah, finally.
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